The Giants locked up one of their key players for the foreseeable future Tuesday, reaching an agreement with shortstop Brandon Crawford on a six-year contract through 2021.
The deal is worth $75 million and covers Crawford’s remaining two arbitration years and first four years of free agency. In addition to a $1.2 million signing bonus, Crawford will make $5.8 million in 2016, $8 million in 2017 and $15 million in each of the following four seasons. The deal includes a full no-trade clause.
The Giants have a recent history of signing their young stars to long-term contracts and started discussing a deal with Crawford earlier this season. Crawford, 28, then validated those discussions by having the best season of his career.
Crawford became the first Giants player since Barry Bonds in 1997 to win both the Gold Glove and Silver Slugger awards in the same season. He recorded career bests in batting average (.256), home runs (21), RBIs (84) and on-base plus slugging (.782), and was named an All-Star for the first time.
Never miss a local story.
A Bay Area native, Crawford has already been a part of two World Series titles with the Giants in 2012 and 2014. Despite missing time last season because of oblique and calf injuries, Crawford has also been durable, playing at least 143 games in each of his four full major-league seasons.
Giants President and CEO Larry Baer said in a news release that Crawford is “an integral part of the team whose performance on the field will be one of the keys to our success for years to come.”
General manager Bobby Evans added that Crawford made “great strides both offensively and defensively last season” and “earned this (contract) through his hard work, dedication and competitive spirit.”